Question

use the given zero to find all zeros of the function
h(x)=3x^3-4x^2+8x+8
zero: 1-√(3i)

Answer 1

one root will be the compliment of the complex number
that is 1+√(3i)

Answer 2

another root is probably real
a factor of 8 divided by 3 could be a root
h(2/3) = 8/9 - 4*4/9 + 16/3 + 8 = not = 0

Answer 3

use this
sum of roots of ax^3 + bx^2 +cx + d = -b/a

Answer 4

try -2/3
i'll use my calculator

- yes thats the one

-2/3 is a zero

so all zeros are 1+√(3i), 1-√(3i) and -2/3

Answer 5

you can often make a good guess of the zero by considering the coefficient of x^3 and last number - here they are 3 and 8