Question

another difficult question, please help

Answer 1

\[\sqrt{x}=-7, then x=49\]

Answer 2

true or false

Answer 3

\[\sqrt x = -7\]
try squaring both sides

what do you get?

Answer 4

49!

Answer 5

so therefore...is it true or false?

Answer 6

false because it actually has to equal -49, the negative sign just never showed up. or would it still be true?

Answer 7

wait...you said then x = 49...

is it 49 or -49? the question i mean

Answer 8

its x=-49

Answer 9

ahh then it is false

Answer 10

-7^2 can never equal -49

Answer 11

it depends on a few things really;

Answer 12

but \[\sqrt x = -7\]
i doubt this will be -49

Answer 13

in general, a sqrt function can never be negative

Answer 14

can it? o.O

Answer 15

but using the quadratic formula as an example

sqrt(49) gets us 7 and -7 for answers ....

Answer 16

sorry to interrupt
but square root of a real number is always positive

\[\sqrt{x} is always positive\]
Thats why whenever u find the roots of quadratic its:
\[x = (-b \pm \sqrt{D})\div 2*a\]
see its \[\pm \sqrt{D}\]

Answer 17

i need help with this also

\[\sqrt[3]{x^2}\]

Write using a fractional exponent.

Answer 18

\[\sqrt[b]{n^a}=n^{a/b}\]