Question

the parabola x= -y^2 + 2y -3
a) lies completely to the right of the y-axis
b) lies completely to the left of the y-axis
c) touches the y-axis
d) crosses the y-axis at two different points

Answer 1

i would like to know how to get the vertex from this equation.

Answer 2

x = a(y – k)2 + h C,how can i get the second equation from the 1st?

Answer 3

@amistre64

Answer 4

y-k
y-k
-----
yy-ky
-ky+kk
----------
y^2-2ky+k^2 ; times it by a and add in h

Answer 5

whats a "second" equation?

Answer 6

either way, we should find the determinant

Answer 7

i wanted to know how to get x = a(y – k)2 + h, from x= -y^2 + 2y -3

Answer 8

Just use completing the square?

Answer 9

b^2 - 4ac

< 0 = doesnt touch y axis

> 0 = touches in 2 spots

=0 touches in 1 spot

Answer 10

yes, completing the square is the usual method

Answer 11

ah okay thank you! :)

Answer 12

but, i would use the determinant to find the answer :)

Answer 13

then wether its left or right depends on?

Answer 14

x= -y^2 + 2y -3

since it starts as a -, this thing opens to the left; since -x is always on the left

Answer 15

okay thank you (:

Answer 16

yw