Question

The rms speed of CH4 is 3.8 * 10^4 cm/s the total kinetic energy of a mixture of 0.8 moles of CH4
and 0.2 moles of C4H10 is?

Answer 1

@ujjwal

Answer 2

masses of CH4 and C4H10 are in the ratio 8:29
so, their rms velocity of C4H10=7.2 * 10^4 cm/s=7.23*10^2 m/s(approx)
total KE of mixture=\[\frac{1}{2}[m_{CH4}\times v_{CH4}^2*0.8N_A+m_{C2H10} \times v_{C4H10}^2 \times 0.2 N_A]\] where \(N_A \)=6.022*10^23

Answer 3

*the

Answer 4

@ujjwal the answert should be 1156 J

Answer 5

It has lots of weird numbers with decimal.. And i don't feel like calculating the whole thing. Did you solve it?
Don't you get the answer?

Answer 6

let me do it

Answer 7

i gussed

Answer 8

i gussed becoz there are many 10^x numbers so how will the answer be correct

Answer 9

Do calculations in SI units.

Answer 10

i got 1676

Answer 11

*10^24

Answer 12

wait @ujjwal um how did u get velocity of c4h10

Answer 13

That's such a large value.. Either i am wrong or your calculation is wrong.

Answer 14

ok u used inverse root thing?

Answer 15

@A.Avinash_Goutham By using the relation \[v_{rms}=\frac{K}{\sqrt M}\] Ypu already have \(v_{rms}\) of CH4. so, knowing the ratio of masses would do.

Answer 16

fine @Yahoo! try using this 3/2 nrt and u l get temp by using velocity

Answer 17

wat is 3/2 nrt

Answer 18

it's energy of a gas.....

Answer 19

did nt understand

Answer 20

um like .5 m v*v = 3/2 nRT

Answer 21

ok......