Question

Separable ODE quick question

Answer 1

My final solution is z = e^e^x+c -3

I am not sure if its right though but wolfram has a completely different answer I do not understand how.

Answer 2

I divided by 3+z^2 and multiplied by dx

Answer 3

So I have z/(3+z^2) = e^x dx

Answer 4

Then 1/(3+z) = e^x dx

Integrate both sides ln 3+x = e^x

Answer 5

Cancelling out the natural log on LHS and subtracting both sides by -3 to give me z = e^e^x+c -3

Answer 6

You have lost dz when divided

Answer 7

You it should be like 1/(3+z) dz = e^x dx

Answer 8

z dz/(z^2+3) = e^x dx

Answer 9

And integrating (1/2)ln(z^2 +3) = e^x + c

Answer 10

So I problem was dividing the dominator and numerator z's..

Answer 11

I don´t understand what you are saying (not very good english, sorry), but you can put it like: ln {sqrt(z^2 +3) = e^x +c

Answer 12

It's cool. What I was doing is z/(3+z^2) ....1/(3+z)

Answer 13

And where did you put that "z"?