Question

What is the equation in standard form of the line which passes through (–2, –3) and has a slope of 1/2?

Answer 1

@Eyad could u help me again

Answer 2

2x + y = 4

2x – y = 4

x + 2y = 4

x – 2y = 4

Answer 3

sure,
Use the law : y2-y1=m(x2-x1)
where (-2,-3)=(x1,y1) ,and m=slope..
can u do it now ?

Answer 4

this is where im stuck

Answer 5

The point–slope form of the equation for a line passing through the point (x1,y1) is given by:

Assuming (-2, –3) = (x1, y1) and m = 172 and substituting the values, we get:

Y-Y1=m(X-X1)
Y-(-3)=1/2(x-(-2))
Y+3=1/2(X+2)
Y+3=1/2X+1
Y=1/2X-2

Answer 6

m=1/2 not 172 lol , the answer is correct , as pointed above

Answer 7

im still confused

Answer 8

OK Then:
y-(-3)=1/2(x-(-2))
y+3=1/2x+1
y=1/2x-2----------> (multiply by 2)
2y=x-4 Or in another form x – 2y = 4
____
Got it ?

Answer 9

not really but thanks anyway

Answer 10

what part you didn't understand ,I just fill up the rule ?

Answer 11

what seems to be the problem , everything is clearly written ---

Answer 12

how did u get 172?

Answer 13

its not 172 ,, i meant to write 1/2

Answer 14

ohh ok i get it then

Answer 15

ok .