how do you work out √3:(-54x^9y^4) ? that's an index of 3 square root -54x^9y^4

Question

how do you work out √3:(-54x^9y^4) ?  that's an index of 3 square root -54x^9y^4

anonymous · Answer

$$\sqrt[3]{-54x^9y^4}?$$

anonymous · Answer

hi...i'm new to this...trying to figure it out...do you know how to work that problem?

anonymous · Answer

For the -54 use a factor tree. Since the index is 3, triples come outside and the two stays under the radical. And you can bring the negative out as well.
|dw:1341263386296:dw|
For the variables, divide the exponents by 3. The cube root of x^9 is x^3.
When you divide 4 by 3 you have a remainder of 1. So y is outside the radical, but you have one remaining inside. 
The solution is 
$$-3x ^{3} y \sqrt[3]{2y}$$