Question

how do you work out √3:(-54x^9y^4) ? that's an index of 3 square root -54x^9y^4

Answer 1

\[\sqrt[3]{-54x^9y^4}?\]

Answer 2

hi...i'm new to this...trying to figure it out...do you know how to work that problem?

Answer 3

For the -54 use a factor tree. Since the index is 3, triples come outside and the two stays under the radical. And you can bring the negative out as well.

For the variables, divide the exponents by 3. The cube root of x^9 is x^3.
When you divide 4 by 3 you have a remainder of 1. So y is outside the radical, but you have one remaining inside.
The solution is
\[-3x ^{3} y \sqrt[3]{2y}\]