Question

would this be a true statement?
\[u=\sqrt{6}{x}\]
therefore...
\[u^2=\sqrt{3}{x}\]

Answer 1

i meant the 6th root

Answer 2

typo

Answer 3

sixth root of x
and
3rd root of x

Answer 4

±

Answer 5

what do you mean?

Answer 6

thats right

Answer 7

yeah i guess \[\frac 1 2 *\frac 1 3 \]

Answer 8

no

Answer 9

\[u=\pm\sqrt[6]{x}\]\[u^2=\sqrt[3]{x}\]

Answer 10

i mean
\[x^{\frac 1 2 *\frac 1 3}\]

Answer 11

just notice
\[\sqrt[a]{x}=x^{1/a}\]
and
\[(x^b)^c=x^{bc}\]

Answer 12

i agree

Answer 13

\[u=x^{\frac 1 2 *\frac 1 3}\] correct?

Answer 14

why not?

Answer 15

i my notation wrong or the idea all together

Answer 16

sorry thats right

Answer 17

well what then?

Answer 18

nothing.
\[u^2=\sqrt{3}{x}\] (cube root) didn't look right to me at first but then it made sense...thanks!