Question

help! plzz ! can someone help me Write the equation of the line which passes through (–4, 2) and is parallel to y = –x + 6 in slope-intercept form.

Answer 1

since the line has to be parallel, do you know what slope it must have?

Answer 2

-1?

Answer 3

good... so m=-1 is your slope, and the given point is (-4, 2).. put these two knowns into point-slope form then put it into slope-intercept form by solving for y..
point-slope form: \(\large y-y_1=m(x-x_1) \)

Answer 4

Yes I was doing that but, whe I got to y-2=-1(x+4) I dont know if whe I distribute the -2 I should make it positive or negative like this, y-2=-1+-4
or negative?

Answer 5

on the right side, distribute the -1 first... what do you get?

Answer 6

I mean-1x+-4

Answer 7

yes.. that's correct... but simplified, that right side is -1x-4

Answer 8

or -x-4

Answer 9

so the plus sign passes to be negative?

Answer 10

yes... for example, it's like this 5 + -3 = 5 - 3, right?

Answer 11

yes

Answer 12

And then I add 4 in both sides?

Answer 13

wich is 0?

Answer 14

no... you want y by itself on the left...

Answer 15

get rid of that -2 by adding 2 to both sides...

Answer 16

oh no I have add 2 in both sides

Answer 17

yes

Answer 18

correct....:)

Answer 19

so I have left y=(-x)-(-2) right?

Answer 20

no... try again...

Answer 21

I make everything positive? Am always having trouble when I have to change it from posive or from negative

Answer 22

\(\large y-2=-x-4 \)
\(\large y-2\color{red}{+2}=-x-4\color{red}{+2} \)
\(\large y=-x-2 \)

Answer 23

oh I get it , so that is the equation they are asking me for?

Answer 24

yes...

Answer 25

Ok thank you so much!
Oh I have another question I you could please help me?
Do I have to always use the fomula for this kind of problems?