Question

??? Can someone help me to Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form

Answer 1

I can help you with it. Do you have a specific question on the method to solve it?

Answer 2

??

Answer 3

the formula I have is this
Y-y1=m(x-x1)

Answer 4

You have all the information needed?
Step one: Determine slope of the line you are to write the equation for. Do you know how to do that?

Answer 5

O.K that will work, do you know how to determine m (the slope)?

Answer 6

I kind of know but I have a huge confusion I dont undestand when do I have to use the formula , because there are examples problems in which they dont use the formula

Answer 7

O.K. The slope m for your line is going to be the negative reciprocal of the slope of the line it is perpendicular to y=4x+7, the coefficient of the x term is the slope of that line, as you can see that slope is 4. What would be the negative reciprocal of 4?

Answer 8

The reciprocal of a number is another number when multiplied equals 1. Example reciprocal of 2 is 1/2. Do you understand?

Answer 9

-4 or 1/4

Answer 10

-1/4

Answer 11

Kind of combine what you have, reciprocal of 4 is 1/4 and the negative makes it -1/4

Answer 12

ok

Answer 13

O.K. now use your equation, that you said you were going to use, plug in -1/4 for m and use your given point (2, -3)

Answer 14

Plug in the Y1 and X1 values.

Answer 15

\[y-(-3)=-1/4(x-2)\]

Answer 16

now I distributed
y-(-3)=-1/4x-(-1/2) am I right?

Answer 17

do I have to make that positive?

Answer 18

Well let me see Your equation was (y-y1) = m(x-x1)
plugging in our values (y-(-3))= -1/4(x-2)
y+3=-x/4+1/2
y=-x/4 -2 1/2

Answer 19

You could put in the same form, but you are correct. Slope intercept form is
y=mx+b

Answer 20

Sorry, but I gotta run, but you have a handle on it. good luck with them.

Answer 21

Ok thank you so much for ur help