Question

Given points A(0,2) and B (-5,15)
when a right triangle is drawn to find the distance between A or B, Find the length of a horizontal leg using Pythagorean thereom. If can , can some draw to scale so i could grasp it better

Answer 1

@Calcmathlete hi. could you draw this one like you drew the other . the only way i could grasp this

Answer 2

this question makes no sense.... you don't need pythagoras's theorem to find the horizontal leg...

Answer 3

You don't really need the drawing to do this kind of thing. JUst find the distance between the x-values and y-values to get the two legs of the pythagorean theorem.
|0 - - 5| = 5
|2 - 15| = 13
The two legs are 5 and 13.
Here's a drawing anyway :)

Answer 4

Actually, yeah. I agree with @campbell_st I solved the horizontal leg without Pythagorean Theorem. TO use it to solve it involves a lot more work...

Answer 5

sooo how do i do it , if not PT ?

Answer 6

you can find the hypotenuse ( longest side) of the triangle using pythagoras' theorem... thats about it

Answer 7

Take a look at the part above my drawing. Subtract the x-values and find the absolute value of that.
|0 - - 5| = = |0 + 5| = 5

Answer 8

That's how I'd do it without Pythagorean Theorem...it's more like a preparation for Pythagorean THeorem...

Answer 9

my answer was 13 . am i right

Answer 10

Again, I just showed it to you right here:
|0 - - 5| = = |0 + 5| = 5

Answer 11

nope... the answer for the length AB is

\[AB = \sqrt{194}\]