Find the absolute value of each complex number. |7 - i|
I know the answer is 5sqrt(2), but I don't know how they got that
|a+bi| = sqrt(a^2+b^2) |7+(-1)i| = sqrt(7^2+(-1)^2) I'll let you take it from here
why did you get rid of the i in sqrt(7^2+(-1)^2)?
You use the formula |a+bi| = sqrt(a^2+b^2) In the case of 7 - i, it's in the form 7+(-1)i which means a = 7 and b = -1
So you plug those values into the formula |a+bi| = sqrt(a^2+b^2)
Wait I don't understand... isn't i = sqrt(-1)?
yes, but with that formula, you only worry about the coefficients
What do you do with the i?
If you plot 7 - i in the complex number plane, you're basically plotting the point (7,-1) on the xy coordinate system To find |7-i|, you're finding the distance from (0,0) to (7,-1)
So you can see that finding the distance from (0,0) to (7,-1) doesn't involve the term i
ooh
glad things are clicking
Thanks!
yw
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