Question

Urgent PLEASEEEE Help!
Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3).

a.y=3/2x-1
b.y=3/2x+3
c.y=-2/3x-1
d.y=-2/3x+3

Answer 1

What is the slope of your line?

Answer 2

y = 3/2x + 4 i think . I'm not really good with this

Answer 3

your equation is in the form y=mx+b, correct?

Answer 4

yes

Answer 5

this website is hard to use

Answer 6

ok, so... m = slope, correct?

Answer 7

yes I believe so

Answer 8

what is your slope?

Answer 9

3/2x ?

Answer 10

its 3/2... yes. soo to find the slope that is perpendicular, you should find the negative reciprical

Answer 11

so -2/3x?

Answer 12

yes.
you need three things to find the slope of a line....

point, which you have (-6,3)
slope, which you just found... m=-2/3
and a form, y-y1=m(x-x1)
so... y-3=-2/3(x+6)

do you see how I got that?

Answer 13

three things to find the equation of a line(sorry)

Answer 14

yeah I understand how you got it :)

Answer 15

then you just solve for y...
y-3=-2/3x -4
y=-2/3x-1

Answer 16

do you understand?

Answer 17

Thank you so much! That really helped me understand how to solve problems like that. Thank you again!

Answer 18

Just remember... you need three things to find the equation of a line:
point (x,y)
slope of m
and a form (y-the given y)=m(x-the given x)
and then you just solve for y

Answer 19

thanks I will remember that next time!