Question

Simplify: x^2 - 16/4x divided by ( x-4 )

Answer 1

Apply the identity \(a^2 - b^2 = (a+b)(a-b)\) to factor x^2 - 16
\[\large \frac{\frac{x^2 - 16}{4x}}{( x-4 )}\]\[\large =\frac{\frac{(x+4)(x-4)}{4x}}{( x-4 )}\]\[\large =\frac{(x+4)(x-4)}{4x( x-4 )}\]Cancel the common factor. Can you do it?

Answer 2

yeah its x+4/4x

Answer 3

Yup :)

Answer 4

thanks for helping :)