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Simplify the expression √¯-25 over (5 - 2i) + (1 - 4i)
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\[\frac{\sqrt{-25}}{(5 - 2i) + (1 - 4i)}\] Consider the denominator, (5-2i) + (1-4i) = 6 - 6i Consider the numerator, \(\sqrt{-25}=5i\) So, \[\frac{\sqrt{-25}}{(5 - 2i) + (1 - 4i)}\]\[=\frac{5i}{6 - 6i}\]\[=\frac{5i}{6(1 - i)}\]Multiply the fraction by a conjugate \(\frac{1+i}{1+i}\) \[=\frac{5i}{6(1 - i)}\times \frac{1+i}{1+i}\]\[=\frac{5i(1+i)}{6(1 - i)(1+i)}\]\[=\frac{5i+5i^2}{6(1^2 - (-1))}\]\[=\frac{5i+5(-1)}{6(2)}\]\[=\frac{5i-5}{12}\]
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