Question

Find the Maclaurin series of f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do not show that \[R_n (x0) \rightarrow 0\]
f(x)=cosh x

Answer 1

\[f(x)=f(0) + f'(0)x +f''(0)x ^{2}/2!+...+f ^{n-1)}(0)x ^{n-1}/n-1!+f ^{n+1)}(x)x^{n+1}/n+1!\]

Answer 2

This is my first time doing any type of problem with Maclaurin series, can you explain it to me?

Answer 3

maclaurin series is taylor series in x0 =0. If you know tayloer series, Maclaurin is just a special case of it

Answer 4

Taylor series is the next section, which I haven't covered yet....sorry I'm such a pain

Answer 5

so then jus read it, :) It's to long to explain from 0. Just could say, that the taylor series is the way to aproximate the value of the function by a polinomial expression which is more comfortable to deal with.

Answer 6

i see

Answer 7

what's the primary difference b/w a taylor and maclaurin series?

Answer 8

taylor series is a general case. Maclaurin series is taylor series at x0=0

Answer 9

fair enough :) thanks

Answer 10

yw