The following data has been collected by a technician:
Gas volume: V = 0.8 m3
Gas pressure: p = 160 kPa
Compression index: n = 1.4
Pressure/volume relationship: pVn = C
Work done = ∫_(V_1)^(V_2)▒〖p dV〗
You first need to work out C, the value of the pressure/volume relationship.
Calculate the work done in compressing the nitrogen from 0.8 m3 to 0.6 m3 using:
integral calculus
Simpson’s rule

Question

The following data has been collected by a technician: 
	Gas volume: V = 0.8 m3 
	Gas pressure: p = 160 kPa 
	Compression index: n = 1.4 
	Pressure/volume relationship: pVn = C 
	Work done = ∫_(V_1)^(V_2)▒〖p dV〗
You first need to work out C, the value of the pressure/volume relationship. 
Calculate the work done in compressing the nitrogen from 0.8 m3 to 0.6 m3 using: 
	integral calculus 
	Simpson’s rule

anonymous · Answer

this is simple ,just go for integration for given limits

anonymous · Answer

and  for simpson's 3rd rule go for some spacing  like from 0.8 to 0.6 in steps as from 0.8 to o.75 .then from 0.75 to .70 and so on then apply simpson"s formulae

anonymous · Answer

\int_{a}^{b} f(x) \, dx \approx \frac{b-a}{6}\left[f(a) + 4f\left(\frac{a+b}{2}\right)+f(b)\right].