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Mathematics 8 Online
OpenStudy (anonymous):

What method(s) would you choose to solve the equation 2x² +4x - 3 = 0

OpenStudy (lgbasallote):

i would use quadratic formula because this isn't factorable...i dont know with you though

OpenStudy (lgbasallote):

what do you mean?

OpenStudy (lgbasallote):

what are the factors of 3?

OpenStudy (lgbasallote):

what are the factors of -3*

OpenStudy (lgbasallote):

haha =)) that's fine..wit practice you'll get it ^_^

OpenStudy (lgbasallote):

you dont need further help anymore?

OpenStudy (lgbasallote):

regarding this problem i mean

OpenStudy (lgbasallote):

sure sure! ^_^

OpenStudy (lgbasallote):

ahh i see...well do you know the concept of the discriminant?

OpenStudy (lgbasallote):

\[\huge b^2 - 4ac > 0 \rightarrow \text{2 real solutions}\] \[\huge b^2 - 4ac = 0 \rightarrow \text{1 real solution}\] \[\b^2 - 4ac < 0 \rightarrow \text{no real solution}\] familiar?

OpenStudy (lgbasallote):

that last line was \[\huge b^2 - 4ac < 0 \rightarrow \text{no real solution}\]

OpenStudy (lgbasallote):

does that sound familiar?

OpenStudy (lgbasallote):

haha it's with experience :) it just becomes natural

OpenStudy (lgbasallote):

so there will be 2 real solutions when b^2 - 4ac so let's look at our expression x^2 + 3x + j what's a?

OpenStudy (lgbasallote):

what's a in x^2 + 3x + j?

OpenStudy (lgbasallote):

okay..remember the general form \[ax^2 + bx + c\] a is the number beside x^2 so what's a in x^2 + 3x + j?

OpenStudy (lgbasallote):

a is the number beside x^2 3 is beside x NOT x^2

OpenStudy (lgbasallote):

haha that's fine..get back to this topic when you want to

OpenStudy (lgbasallote):

lol deleted all your replies?

OpenStudy (lgbasallote):

it's actually pretty obvious you know..not the cleverest move you could've made

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