What method(s) would you choose to solve the equation 2x² +4x - 3 = 0
i would use quadratic formula because this isn't factorable...i dont know with you though
what do you mean?
what are the factors of 3?
what are the factors of -3*
haha =)) that's fine..wit practice you'll get it ^_^
you dont need further help anymore?
regarding this problem i mean
sure sure! ^_^
ahh i see...well do you know the concept of the discriminant?
\[\huge b^2 - 4ac > 0 \rightarrow \text{2 real solutions}\] \[\huge b^2 - 4ac = 0 \rightarrow \text{1 real solution}\] \[\b^2 - 4ac < 0 \rightarrow \text{no real solution}\] familiar?
that last line was \[\huge b^2 - 4ac < 0 \rightarrow \text{no real solution}\]
does that sound familiar?
haha it's with experience :) it just becomes natural
so there will be 2 real solutions when b^2 - 4ac so let's look at our expression x^2 + 3x + j what's a?
what's a in x^2 + 3x + j?
okay..remember the general form \[ax^2 + bx + c\] a is the number beside x^2 so what's a in x^2 + 3x + j?
a is the number beside x^2 3 is beside x NOT x^2
haha that's fine..get back to this topic when you want to
lol deleted all your replies?
it's actually pretty obvious you know..not the cleverest move you could've made
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