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Mathematics 8 Online
OpenStudy (anonymous):

To the nearest tenth, what is the area of the shaded segment when BN = 8 ft? I tried using Area of Sector=(155/360)*3.14(8)² But what I come up with isn't a choice

OpenStudy (anonymous):

OpenStudy (anonymous):

what are the options??

OpenStudy (anonymous):

72.8 ft2 53.2 ft2 22.6 ft2 39.3 ft2

OpenStudy (anonymous):

i am getting 67.04. Are you sure we want the area of sector or it is area of segment??

OpenStudy (anonymous):

To the nearest tenth, what is the area of the shaded segment when BN = 8 ft? Segment

OpenStudy (callisto):

Area of sector NWB = \(\pi r^2 \times \frac{\theta}{360}\) = \(\pi (8)^2 \times \frac{120}{360}\) = \(\frac{64}{3}\pi\) Area of triangle NWB = \(\frac{1}{2}r^2sin120\) = \(\frac{1}{2}(8)^2sin120\) = \(16\sqrt3\) Area of shaded region = Area of sector NWB - Area of triangle NWB = \(\frac{64}{3}\pi -16\sqrt3\) = ...?

OpenStudy (anonymous):

Thanks man, 39.3

OpenStudy (callisto):

You're welcome! For your information, I'm not a gentleman though.

OpenStudy (anonymous):

Haha, sorry. Could you help me with the next shaded one? I guess I am terrible at them lol

OpenStudy (callisto):

Let see. Please close this question and start a new post for the new question.

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