To the nearest tenth, what is the area of the shaded segment when BN = 8 ft? I tried using Area of Sector=(155/360)*3.14(8)² But what I come up with isn't a choice
what are the options??
72.8 ft2 53.2 ft2 22.6 ft2 39.3 ft2
i am getting 67.04. Are you sure we want the area of sector or it is area of segment??
To the nearest tenth, what is the area of the shaded segment when BN = 8 ft? Segment
Area of sector NWB = \(\pi r^2 \times \frac{\theta}{360}\) = \(\pi (8)^2 \times \frac{120}{360}\) = \(\frac{64}{3}\pi\) Area of triangle NWB = \(\frac{1}{2}r^2sin120\) = \(\frac{1}{2}(8)^2sin120\) = \(16\sqrt3\) Area of shaded region = Area of sector NWB - Area of triangle NWB = \(\frac{64}{3}\pi -16\sqrt3\) = ...?
Thanks man, 39.3
You're welcome! For your information, I'm not a gentleman though.
Haha, sorry. Could you help me with the next shaded one? I guess I am terrible at them lol
Let see. Please close this question and start a new post for the new question.
Join our real-time social learning platform and learn together with your friends!