Question

Solve:
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Answer 1

The number N=\[N=6\log_{10}2+\log_{10}31\] lies between two successive integers whose sum is equal to-
a)5 c)9
b)7 d)10

Answer 2

@ganeshie8 @apoorvk @TuringTest

Answer 3

\[N = 6log_{10}2 + log_{10}31= log_{10}2^6+log_{10}31\]\[ = log_{10}(2^6\times 31)=log_{10}1984=3.2975...\]
Can you do it now???

Answer 4

how to find that value of log1984??

Answer 5

Can you use calculator?

Answer 6

No

Answer 7

Alright... Then....
log1000<log1984 <log10000
log 10^3 < log 1984 < log10^4
3< log 1984 < 4
Got it?

Answer 8

ok thanks

Answer 9

Welcome. Hope it helps...