Simplify by expressing fractional exponents instead of radicals.
\[\sqrt[8]{x^2y^4}\]
remove common factors, namely 2 and get \[\sqrt[4]{xy^2}\] no need for exponentials for this problem
by "remove common factors" i should say "factors in common in the index and radicand"
I don't understand. could you please explain.
yes the index is 8 the radicand (the expression inside the radical) is \(x^2y^4\) and each exponent has a factor of 2 so you can divide each by a factor of 2 8 divided by 2 is 4, 2 divided by 2 is 1, 4 divided by 2 is 2, you get \[\sqrt[4]{xy^2}\]
you can also rewrite at \[(x^2y^4)^{\frac{1}{8}}=x^{\frac{2}{8}}\times y^{\frac{4}{8}}=x^{\frac{1}{4}}\times y^{\frac{2}{4}}\] if you like, but it seems like a large waste of time
or even \(x^{\frac{1}{4}}\times y^{\frac{1}{2}}\)
could you please help me with another. it is: \[\sqrt[8]{y^2}\]
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