Question

Plz help:)

Answer 1

can you rewrite it using paranthesis ?

Answer 2

okay let me provide a hint:
\[\log_ab^n = n\log_ab\]

Can you apply this to the very first term?

Answer 3

Sorry, for misunderstanding all of u.My ques. is:-\[\log_{5}{(5^{1/x}+125)} =\log_{5}{6+1+(1/2)x} \]

Answer 4

@apoorvk Plz help:)

Answer 5

\(1 = \log_55\) and \(x/2= \log_55^{x/2}\)

Replace it and then club the logs together. And then solve!

Answer 6

can u give me full solution plz.

Answer 7

Do you know the properties of logarithms?

Answer 8

Ya!

Answer 9

are u there @apoorvk ?

Answer 10

okay, what's --> \(\log_56+\log_55 + \log_55^{x/2}=??\)

Answer 11

I couldn't understood wht u wants to say:(

Answer 12

Is anybody here????

Answer 13

Plz help.
I need helppppppppppp.

Answer 14

do you know that \(\log_ma+\log_mb+....+\log_mn=\log_m(a\times b\times....\times n)\)??

Answer 15

ya!

Answer 16

so can you apply that to the expression I wrote above and find out its equivalent?

Answer 17

I gt \[\log_{5}{30\times5{x/2}} \]

Answer 18

@apoorvk

Answer 19

that would be actually \(\log_5(30\times 5^{x/2})\) that's what you meant right?

Answer 20

Ya!

Answer 21

Hmm, so now this term equals the LHS, that is \(\log_5(5^{1/x}+ 125)\).
Now since the bases are same, you can take antilog and remove the log signs, so that the arguments equal each other.

(Btw, are you sure that the '125' is a part of the argument of the log in the LHS?)

Answer 22

Ya!i m totally sure that 125 is a part of the argument of the log in the LHS.

Answer 23

The answer given in my book is 1/2 or 1/4.

Answer 24

One minute I think at R.H.S.the argument of log is only to 6.

Answer 25

so, \(5^{1/x}+125 = 30\times 5^{x/2}\)

Answer 26

WHAT?? I REQUEST you to please read it correctly yaar, ye toh paagal ho gaya main :O
:p

Answer 27

Nooooo ! I m only thinking about this becoz at R.H.S. there is no bracket like those at L.H.S.

Answer 28

Do u understand??????

Answer 29

I have written the correct ques.

Answer 30

Itna sannata kyun hai????

Answer 31

http://www.wolframalpha.com/input/?i=Solve [Log[30*5^%28x%2F2%29]+%3D%3D+Log[125+%2B+5^%281%2Fx%29]%2C+x]

Answer 32

so wht is ur conclusion @experimentX

Answer 33

must be some kind of typo in question.

Answer 34

K! I gt it .i also thought that there is some type of typo.
Thanx!

Answer 35

if the answer is 1/2 and 1/4 then there must be some typo. try solving by pluggin to wolfram.

Answer 36

K!