Question

Assume that you have 3.15 grams of the deadly gas hydrogen cyanide,HCN . What is the volume of the gas at STP?

Answer 1

The density at STP is ~687 \(\frac{mg}{mL}\) from my appendix. Can you now convert this into a volume based on the mass? :-)

density = mass / volume , as you can see from the units above

Answer 2

Careful though because the density is given in milligrams and you were given 3.15 grams, and you answer should have 3 sig figs.

Answer 3

I'm not ever sure what you're asking me to do...

Answer 4

How many grams per milligram (mg)?
How many liters per milliliter(mL)?

Answer 5

3.15

Answer 6

100

Answer 7

not3.15

Answer 8

What? No 3.15g is the mass you have.

\(\frac{1}{1000}\)="milli-" prefix

Answer 9

If you have 687 mg and you convert to grams, how much is this?

Answer 10

.0687

Answer 11

Did you mean 0.687? What you wrote was technically incorrect

Answer 12

.687 is correct.

Answer 13

\[687 \frac{\cancel{mg}}{\cancel{mL}} * \frac{1 g}{1000 \cancel{mg}} * \frac{1000 \cancel{mL}}{1 L} = ?\]

\[\rho = \frac{mass}{volume}\]
\[\rho*volume = mass\]
\[volume = \frac{mass}{\rho}\]

Check:
\[L = \huge \frac{g}{(\frac{g}{L})} = \large \frac{g}{1}*\frac{L}{g}\]


Make sense now @klag84

Answer 14

? :-)

Answer 15

\(\rho\) = rho = international symbol for density that everybody uses, the density is measured relative to a temperature or a phase state (i.e.: solid, liquid, gas) that is dependent on temperature. All I did was Google the STP density of Hydrogen Cyanide and found a table with it on there. :-)

Answer 16

The only problem was it was in different units than what you're using, so I showed you how to convert above to the units you do need.

Answer 17

Does this give me the final answer?

Answer 18

I got the answer

Answer 19

"What is the volume of the gas at STP?" yes.

It depends on the source though, http://www.wolframalpha.com/entities/chemicals/hydrogen_cyanide/bx/aq/hg/ Close but a slightly different density, see?

Answer 20

Are you sure you weren't given the density of the gas with this problem? If you want to be safe, run both density answers through and give your answer as a range. That's what I'd do if my boss was asking that question to me, give him a range (as low as this to as high as this)