OpenStudy (hang254):

Darren designed this triangular shaped entrance, ABC, to a mall. Which expression can be used to find the distance between the points B and C of the entrance? 15/cot65 + 15/sec25 15/cot65 + 15cot25 15/sec65 + 15sec25 15/cot65 + 15/cot25

5 years ago
OpenStudy (hang254):
5 years ago

OpenStudy (osuxbucks15):

can u bump it?

5 years ago
OpenStudy (osuxbucks15):

thanks calc!!!

5 years ago
OpenStudy (osuxbucks15):

Thanks radar

5 years ago
OpenStudy (anonymous):

Let's first work on the triangle on the right. You have the angle value and one side value. If: \[\sec = \frac{hyp.}{adj.}\]\[\cot = \frac{adj.}{opp.}\]which one can you use (you should have one of the values.

5 years ago
OpenStudy (radar):

BD=15/(Cot 65deg DC=15Cot 25 degrees BC=BD+DC

5 years ago
OpenStudy (hang254):

15cos(25

5 years ago
OpenStudy (anonymous):

@hang254 I mean out of sec and cot, which one can you use? sec involves the hypotenuse. SInce you don't have the value of the hypotenuse in either triangle, we will be using cot. Do you understand so far?

5 years ago
OpenStudy (hang254):

yes

5 years ago
OpenStudy (anonymous):

Ok. Knowing he ratio of cot, let's start with the triangle on the right. \[\cot 25º = \frac{adj.}{opp.} = \frac{x}{15}\]what would you do here to get x by itself?

5 years ago
OpenStudy (hang254):

cross multiply

5 years ago
OpenStudy (osuxbucks15):

is ratio used in division

5 years ago
OpenStudy (anonymous):

No. What do you do here to get x by itself: \[\cot 25º = \frac{x}{15}\]

5 years ago
OpenStudy (osuxbucks15):

???

5 years ago
OpenStudy (hang254):

15cot(25 ?

5 years ago
OpenStudy (anonymous):

Yup. THerefore, x = CD = 15cot(25º). Keep this measurement in mind. Now let's move onto the next triangle. \[\cot 65º = \frac{15}{y}\]Get y by itself here.

5 years ago
OpenStudy (hang254):

15/cot65

5 years ago
OpenStudy (anonymous):

Ok. y = BD = 15/cot 65º BD + CD = BC BC = 15/cot 65º + 15 cot 25º which one is this answer?

5 years ago
OpenStudy (anonymous):

*I mean this is your answer :)

5 years ago
OpenStudy (hang254):

option 2

5 years ago
OpenStudy (hang254):

thank you so much, i was confused on that one

5 years ago
OpenStudy (anonymous):

There you go :)

5 years ago
OpenStudy (anonymous):

np :)

5 years ago
OpenStudy (osuxbucks15):

thanks calc

5 years ago