Question

solve the differential eq

y' = 53x * e^x^2

y = ?

Answer 1

\[y' = 53x * e^{x^2}\]

Answer 2

\[\frac{dy}{dx}=53xe^
{2x}\]

Answer 3

2 comes down?

Answer 4

these diff eq's always konfuse me...

Answer 5

Shouldn't I just solve normally by parts?

Answer 6

are you in differential equations

Answer 7

or is this a calculus question

Answer 8

calc 2.

Answer 9

well first multiply by dx

Answer 10

\[dy=e^{x^2}53xdx\]

Answer 11

if you integrate both sides

Answer 12

you get

y=

Answer 13

oh yeah that's right... :P

Answer 14

let u x^2

du=2xdx
du/2=xdx

Answer 15

so hmm. u = 53x
du = 53dx

\[dv = e^{x^2}\]
v = hmm

Answer 16

\[y=53/2\int e^u\]

Answer 17

ah...

Answer 18

no need by parts only ned u sub

Answer 19

okies, I'm thinking too much with mega headache :P.

Answer 20

\[y = \frac{53}{2} \frac{e^{2u}}{2}\]

Answer 21

or would it be... \[e^{u^2}\]

Answer 22

oosp nvm it stays the same...

Answer 23

\[y = \frac{53}{2} * e^u + c\]

Answer 24

\[y = \frac{53}{2} * e^{x^2} + c\]

Answer 25

yep