Question

In the figure above, what is the sum, in terms of n, of the degree measures of the four angles marked with arcs ?
(A) n (B) 2n (C) 180-n (D) 360-n (E) 360–2n

Answer 1

look at question number 47

Answer 2

Here's a hint: the sum of the exterior angle of a triangle (that would be n degrees in this case) is equal to the sum of the opposite two interior angles. You have two pairs of interior angles opposite the exterior angle n. So if each of the two pairs of interior angles is equal to the exterior angle n, their sum would be how many n's?

Answer 3

Does that help?

Answer 4

i have no idea what u r talking about can you just give me the answer to make my life easier plz

Answer 5

OK - let me try to make it a little clearer. If you look at the diagram, you see that angle n is right between the two triangles. It is not a part of either triangle, because it is outside them. That's why it's called an "exterior" angle. Good so far?

Answer 6

I'm ready to give you the part that will allow you to get the answer and make your life easier - just want to be sure you follow so far, so let me know.

Answer 7

i kinda understand so the answer is?

Answer 8

Good. The rule is that an exterior angle to a triangle (like n in your problem) is equal to the two interior angles (the two angles inside the triangle marked with the arcs) on the opposite side. So n is equal to the two angles marked in the left triangle and to the two angles marked in the right triangle. So if each pair of marked angles is equal to n, how many n's do you have?

Answer 9

Did I lose you? The two marked angles on the left =n and the two angles on the right =n.
n+n = ? That would be the sum of the 4 marked angles. Please let me know if you understand

Answer 10

ok so its B?

Answer 11

Absolutely - hope that helped!

Answer 12

i got the answer right

Answer 13

?

Answer 14

yes