Question

how do i simplify:2x-2y/3x+3y muliplied by 6x+6y/x^2-y^2

Answer 1

do you mean
\[ \frac{2x-2y}{3x+3y}\cdot\frac{6x+6y}{x^2-y^2} \]

Answer 2

yes

Answer 3

ok, so
\[ \frac{2x-2y}{3x+3y}\cdot\frac{6x+6y}{x^2-y^2}=
\frac{2(x-y)}{3(x+y)}\cdot\frac{6(x+y)}{(x-y)(x+y)} \]
can you go from here?

Answer 4

so would i just multiply the 2 x 6 first?

Answer 5

no, first you simplify!
which of factors go away?

Answer 6

i think u would cancel (x+y) and (x-y) then u would simplify and get 4/(x+y)

Answer 7

\[ \frac{2(x−y)}{3(x+y)}⋅\frac{6(x+y)}{(x−y)(x+y)}=\frac{2(x-y)}{3(x+y)}\cdot
\frac{3\cdot 2(x+y)}{(x-y)(x+y)} \]
do you get it?

Answer 8

so when i simplify it i get this 6/(x-y) ?

Answer 9

no the answer is
\[ \frac{4}{x+y} \]
do you get it?