how do i simplify:2x-2y/3x+3y muliplied by 6x+6y/x^2-y^2

Question

helder_edwin · Answer

do you mean
$$ \frac{2x-2y}{3x+3y}\cdot\frac{6x+6y}{x^2-y^2} $$

anonymous · Answer

yes

helder_edwin · Answer

ok, so
$$ \frac{2x-2y}{3x+3y}\cdot\frac{6x+6y}{x^2-y^2}=
\frac{2(x-y)}{3(x+y)}\cdot\frac{6(x+y)}{(x-y)(x+y)} $$
can you go from here?

anonymous · Answer

so would i just multiply the 2 x 6 first?

helder_edwin · Answer

no, first you simplify!
which of factors go away?

anonymous · Answer

i think u would cancel (x+y) and (x-y) then u would simplify and get 4/(x+y)

helder_edwin · Answer

$$ \frac{2(x−y)}{3(x+y)}⋅\frac{6(x+y)}{(x−y)(x+y)}=\frac{2(x-y)}{3(x+y)}\cdot
\frac{3\cdot 2(x+y)}{(x-y)(x+y)} $$
do you get it?

anonymous · Answer

so when i simplify it i get this 6/(x-y) ?

helder_edwin · Answer

no the answer is
$$ \frac{4}{x+y} $$
do you get it?