Write the general form of the equation which matches the graph below. In complete sentences, explain the process taken to find this equation
ur having a bad day with parabolas arent you?? lol
yes i am its like the only thing i dont understand :(
whats the dashed line represent any idea??
the directrix
ok cool. its simple. firstly u notice its an inverted parabola??
whats an inverted parabola?
well its upside down....
oh okay so then yeah lol
so doesnt that means it will be negative
so the general equation of a parabola is y=ax^2. are you aware of this?
yes. it will be negative and become y= -ax^2
yes i know the equation just dont no how to write it just by looking at the graph
wait i thought the equation would be y=a(x-h)^2+k since its away from the vertex
but thats not all. you have a particular vertex and directrix of this parabola. so the equation becomes\[(x-h)^{2}=4*p*(y-k)\] where (h.k) is the focus and p is the distance from the vertex to the focus and the vertex to the directrix. you can see this distance to be equal?? (4)
yeah ur right
u forgot to include the y coordinates' shift like u did with the x...
oh okay i think i got that
cool..
but how do i write the equation
simple. h=3. and k= -4. so put that in the equation i wrote along with p=4. there is ur equation.
so i have a question is the parabola at the origin or away from the origin?
away from clearly....if its vertex lies at the origin, then u say it is at the origin. but u can see its not.
so the origin is 0,0 right
so since its at (3,1) its away correct?
yup :)
oh okay got it now
so would the focus be (3,-4)
yup....correction, the vertex is at (3,0) not (3,1). but the focus is at (3,-4). yup
by bad typo thats what i have written down
lol...happens
yeah
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