Question

how do you solve this problem. i'll write it below.

Answer 1

\[x^2-3x-18/ x^2-2x-24\div 1/x+4\]

Answer 2

\[{x^2-3x-18\over x^2-2x-24}\div{1\over x+4}\]

Answer 3

i'm guessing this is the problem:
oops too fast form me but that's exactly what i was writing...^^^

Answer 4

did I type it correctly?

Answer 5

thats the right equation

Answer 6

first step is to factor the left side as much as possible

Answer 7

can you factor\[x^2-3x-18\]can you factor\[x^2-2x-24\]?

Answer 8

yeah, give me a sec to work it out.

Answer 9

okay so for the first equation the answer is (x-6)(x-3)

Answer 10

careful
(-)(-)=+
so (-6)(-3)=+18 and we want -18

Answer 11

we also want the two numbers to add to the middle term, -3, and
-3+(-6)=-9 not -3

Answer 12

(hint: the numbers are right but the signs need adjustment)

Answer 13

I don't know what signs i messed up on. the only numbers i can get is -6 and 3

Answer 14

yes, so it should be (x-6)(x+3)