Question

Here are two probability problems which are more difficult than they look.

1) A coach is training 15 girls. He wants to form 5 lines of 3 forwards each (left-wing, center,and right-wing). Assume that the order of assigning these positions matters. What is the probability that both Ann and May are in the same line?


2) There is a standard deck of 52 playing cards. EACH person is dealt 13 cards. What is the probability that one of the 4 people gets ALL 4 aces?

can anyone help

Answer 1

is this correct::
1) [1/15 x 1/14] +
[14/15 x 13/14 x 1/12 x 1/11] +
[14/15 x 13/14 x 11/12 x 10/11 x 1/9 x 1/8] +
[14/15 x 13/14 x 11/12 x 10/11 x 8/9 x 7/8 x 1/6 x 1/5] +
[14/15 x 13/14 x 11/12 x 10/11 x 8/9 x 7/8 x 5/6 x 4/5 x 1/3 x 1/2]
= 10.25%

Answer 2

I posted it also in physics forum

Answer 3

@lgbasallote

Answer 4

@mathslover

Answer 5

http://www.physicsforums.com/showthread.php?t=268697

Answer 6

yup @mathslover i only posted that

Answer 7

So that is all , u r right : may be m not sure sorry

Answer 8

come on @mathslover

Answer 9

@Master.RohanChakraborty . I know what you feel, but this site does NOT allow the presence of medal parties in anyway.sorry
Thanks

Answer 10

k

Answer 11

THIS QUESTION IS CLOSED