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Mathematics 13 Online
OpenStudy (anonymous):

in the diagram below, the width of the shaded reagion is exactly equal to the radius of the smaller circle (the circles are concentric) What part of the area of the larger circle is the area of the shaded region?

OpenStudy (anonymous):

OpenStudy (shubhamsrg):

you mean what part from the center?

OpenStudy (unklerhaukus):

\[A_{\text {circle}}=\pi r^2\]

OpenStudy (anonymous):

i think it means the area of only the ring

OpenStudy (unklerhaukus):

the ring is a difference of circles

OpenStudy (unklerhaukus):

\[A_{\text {ring}}=\pi R^2-\pi r^2\]\[R=2r\]

OpenStudy (anonymous):

if we take the radius of the smaller circle 'r' then the radius of the bigger one would be '2r' are the shaded are = pi*(2r)^2 - pi*r^2

OpenStudy (anonymous):

area of the shaded are = pi*(2r)^2 - pi*r^2

OpenStudy (anonymous):

so we only need the radius of the smaller circle r

OpenStudy (unklerhaukus):

the question asks for \[\frac{A_{\text{ring}}}{A_{\text {large circle}}}\]

OpenStudy (anonymous):

ok how do we find the radius?

OpenStudy (unklerhaukus):

the radius of the large circle is R=2r

OpenStudy (anonymous):

so it would be like \[(\pi (2r)^2-\pi r^2)/(\pi (2r)^2)\]= 3/4

OpenStudy (unklerhaukus):

i think so

OpenStudy (anonymous):

aright thinks

OpenStudy (unklerhaukus):

yeah that is correct

OpenStudy (unklerhaukus):

it even looks right.

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