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Mathematics 6 Online
OpenStudy (anonymous):

1.Calculate NL. 2.Calculate KN. 3.Calculate MN.

OpenStudy (anonymous):

OpenStudy (helder_edwin):

sorry i misread the graph.

OpenStudy (anonymous):

Not quite. 26 goes to KM and not KN, so you can't use Pythagorean THeorem...yet.. To solve for NL, plug in these values and solve the proportion. \[\frac{KN}{NL} = \frac{NL}{NM}\]

OpenStudy (anonymous):

how about the other ones

OpenStudy (anonymous):

\[\frac{KN}{KL} = \frac{KL}{KM}\]\[\frac{MN}{ML} = \frac{ML}{KM}\]

OpenStudy (shayaan_mustafa):

Hi kathy14 :) How are you?

OpenStudy (shayaan_mustafa):

By the way Calcmathlete seems right. Why don't you follow him?

OpenStudy (shayaan_mustafa):

But there is another way to solve this

OpenStudy (anonymous):

im good and you? do u know how?

OpenStudy (shayaan_mustafa):

Yes me also well. Yes I know. But I want that Calcmathlete see my solution and tell me where I go wrong. So should I start?

OpenStudy (shayaan_mustafa):

First we have to calculate \(\angle K\) Use cosine ratio, Cos\(\theta\)=\(\Large\frac{24}{26}\) \(\theta\)=\(\large \text{cos}^{-1}(0.923)\) \(\theta\)=22.62

OpenStudy (shayaan_mustafa):

Now we know the sum of the all angles in a triangle is 180. So 22.62+90+M=180 M=67.38

OpenStudy (shayaan_mustafa):

Now we have \(\angle\)M So we can find NL

OpenStudy (shayaan_mustafa):

Use sine ratio now, sin(67.38)=\(\Large\frac{NL}{10}\) NL=10*(0.923) NL=9.23

OpenStudy (shayaan_mustafa):

Now use Pythagorean theorem here, MN=\(\sqrt{ML^2+NL^2}\) MN=\(\sqrt{(10)^2-(9.23)^2}\) MN=3.848

OpenStudy (shayaan_mustafa):

Now, KM=KN+MN KN=KM-MN KN=26-3.848 KN=22.152

OpenStudy (shayaan_mustafa):

Now you have all your required sides dear.

OpenStudy (shayaan_mustafa):

May be I have some mistake in calculation because all these calculations are verbally so please check by your own self too. But the procedure will remain same.

OpenStudy (anonymous):

sorry its late. but thank you shayaan_mustafa

OpenStudy (shayaan_mustafa):

you are welcome kathy14 :)

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