1.Calculate NL. 2.Calculate KN. 3.Calculate MN.
sorry i misread the graph.
Not quite. 26 goes to KM and not KN, so you can't use Pythagorean THeorem...yet.. To solve for NL, plug in these values and solve the proportion. \[\frac{KN}{NL} = \frac{NL}{NM}\]
how about the other ones
\[\frac{KN}{KL} = \frac{KL}{KM}\]\[\frac{MN}{ML} = \frac{ML}{KM}\]
Hi kathy14 :) How are you?
By the way Calcmathlete seems right. Why don't you follow him?
But there is another way to solve this
im good and you? do u know how?
Yes me also well. Yes I know. But I want that Calcmathlete see my solution and tell me where I go wrong. So should I start?
First we have to calculate \(\angle K\) Use cosine ratio, Cos\(\theta\)=\(\Large\frac{24}{26}\) \(\theta\)=\(\large \text{cos}^{-1}(0.923)\) \(\theta\)=22.62
Now we know the sum of the all angles in a triangle is 180. So 22.62+90+M=180 M=67.38
Now we have \(\angle\)M So we can find NL
Use sine ratio now, sin(67.38)=\(\Large\frac{NL}{10}\) NL=10*(0.923) NL=9.23
Now use Pythagorean theorem here, MN=\(\sqrt{ML^2+NL^2}\) MN=\(\sqrt{(10)^2-(9.23)^2}\) MN=3.848
Now, KM=KN+MN KN=KM-MN KN=26-3.848 KN=22.152
Now you have all your required sides dear.
May be I have some mistake in calculation because all these calculations are verbally so please check by your own self too. But the procedure will remain same.
sorry its late. but thank you shayaan_mustafa
you are welcome kathy14 :)
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