Question

find the absolute extrema of the following function on the given interval:
f(x) = 6 - (3x / (x^2 + 1)) , [0, positive infinity]

Answer 1

do you have the df/dx ?

Answer 2

i found that the absolute max was 7.5 and the absolute min is 4.5

Answer 3

remember to use the interval given...

Answer 4

@soccergal12
your answers are right

Answer 5

okay thank you

Answer 6

on the interval given, your answer is incorrect....

Answer 7

oh...Oh why?!

Answer 8

@dpaInc

Answer 9

the interval he/she is looking at is [0, infintiy)

Answer 10

well

Answer 11

max is at x=0, f(0)=6

Answer 12

oh yes x=-1 is not in the interval u r right

then absolute maxima is f(0)=6
and absolute minima is f(1)=4.5

am i right?

Answer 13

yep...:)

Answer 14

@dplanc thank u

Answer 15

@soccergal12

Answer 16

oh, yeah. thank you! i didn't realize that either