How would you solve the following geometry problem?:

∆PQR, find the measure of ∡P.

In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown.

Answers:
30.4°

35.9°

54.1°

59.6°

What I did:
equation: tan(x) = 33.8/57.6
tan(x)=0.56
But I know that isn't correct.

Question

How would you solve the following geometry problem?:

∆PQR, find the measure of ∡P.

In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown.

Answers:
30.4°

35.9°

54.1°

59.6°

What I did:
equation: tan(x) = 33.8/57.6  
tan(x)=0.56
But I know that isn't correct.

anonymous · Answer

attachment

shayaan_mustafa · Answer

Hi CDT :)

Nice name :p

How are you?

shayaan_mustafa · Answer

Use tangent ratio

anonymous · Answer

haha thanks. Im alright just trying to solve this.

anonymous · Answer

could you give an example?

shayaan_mustafa · Answer

Tan$\theta$=$\Large\frac{\text{Perp}}{\text{Base}}$

Tan$\theta$=$\Large\frac{33.8}{57.6}$

Tan$\theta$=0.586

$\theta$=$tan^{-1}$(0.586)

$\theta$=30.4

shayaan_mustafa · Answer

lol example. I have solved all. :D

anonymous · Answer

ok so thats how you put the tangent on the other side

shayaan_mustafa · Answer

Yes. When ratios move to others sides of equal then they have inverse.

anonymous · Answer

oh okay thanks a lot:)

shayaan_mustafa · Answer

Ever welcome.