Solve the proportion x over x squared minus 2 equals 2 over 3 times x plus 5.
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OpenStudy (tennistar):
|dw:1341432688324:dw|
OpenStudy (anonymous):
like this?
\[\huge \frac{x}{x^2-2}=\frac{2}{3x+5} \]
OpenStudy (tennistar):
yes
OpenStudy (anonymous):
ok... cross multiplying and you'll end up with:
\[\huge x(3x+5)=2(x^2-2) \]
\[\huge 3x^2+5x=2x^2-4 \]
can you solve this quadratic equation from here?
OpenStudy (tennistar):
um, no
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OpenStudy (anonymous):
ok... get this equation in standard form...
that is make it look like this \(\large ax^2+bx+c=0 \)
OpenStudy (anonymous):
do some algebra to make the right side zero....
OpenStudy (tennistar):
what? Tennis terms?
OpenStudy (anonymous):
lol.... just kidding...
OpenStudy (tennistar):
oh
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OpenStudy (anonymous):
your the tennis star..:)
OpenStudy (anonymous):
need help?
OpenStudy (anonymous):
whatever you do on one side, you do to the other... since we need to make the right side zero, subtract \(\large 2x^2-4 \) from both sides..
\[\huge 3x^2+5x=2x^2-4 \]
\[\huge 3x^2+5x\color{red}{-(2x^2-4)}=2x^2-4 \color{red}{-(2x^2-4)}\]
\[\huge 3x^2+5x\color{red}{-2x^2+4}=0\]
\[\huge x^2+5x+4=0 \]