Mathematics
18 Online
OpenStudy (konradzuse):
integrate
(sin(x))^3
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OpenStudy (turingtest):
now you get to try to be a little clever
OpenStudy (turingtest):
why don't I let you try it first and see how you approach it?
OpenStudy (konradzuse):
\[\int\limits \sin^2(x) \sin(x)\]
\[\frac{1}{2}\int\limits(1-\cos^2(x)) \sin(x)\]
OpenStudy (turingtest):
where did the 1/2 come from?
OpenStudy (turingtest):
I think you are mixing up trig identities
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OpenStudy (konradzuse):
oh woops stupid lecture :P
OpenStudy (konradzuse):
1-cos(2x)/2?
OpenStudy (konradzuse):
it seems I could bring the 1/2 out in front?
OpenStudy (konradzuse):
half angle fomulas hmm and pytagorean formula... Seems you could use either...
OpenStudy (konradzuse):
I konfused myself :P
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OpenStudy (turingtest):
but one choice makes for a two-step problem and the other choice makes for a 3-step problem
OpenStudy (konradzuse):
ok so lets make it easy....
OpenStudy (turingtest):
yes
OpenStudy (konradzuse):
\[\int\limits \sin(x)-\cos^2(x) \sin(x)dx :P\]
OpenStudy (konradzuse):
\[\int\limits \sin(x) dx- \int\limits \cos^2(x) \sin(x)dx\]
u = cos(dx)
du = -sin(x)dx
\[\int\limits \sin(x) dx--\int\limits u^2du\]
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OpenStudy (konradzuse):
\[-\cos(x) + \frac{u^3}{3} + c\]
OpenStudy (konradzuse):
\[-\cos(x) + \frac{\cos(x)^3}{3} + c\]
OpenStudy (konradzuse):
Ok it's right WOOT!
OpenStudy (anonymous):
Refer to the attachment.
OpenStudy (konradzuse):
hmm?
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OpenStudy (konradzuse):
Hope you didn't do it all out all nice and put it into a tiff file... :P
OpenStudy (anonymous):
Part of a screen capture from WolframAlpha.