Question

For h(theta)=1-3tan(theta), use the intermediate value theorem to determine if the function has a 0 on the interval -> [0, pi/4)

Answer 1

i love that name...:)

Answer 2

oh thank you lol

Answer 3

its pretty simple of a name haha

Answer 4

figure out h(0) and h(pi/4)... if they're of different signs, then you know there has to be a zero in the interval because h is continuous...

Answer 5

I'm guessing their is a zero in the interval becausee..

Answer 6

i mean i know i can just plug them in but uhh lol

Answer 7

i'm not sure.

Answer 8

you don't need to guess... that's what the IVt is for... it guarantees their is a zero in the interval...

Answer 9

IVt? lol

Answer 10

and oh alright

Answer 11

IVT - intermediate value theorem...

ok...
what's

h(0) =
h(pi/4) =

calculate these...

Answer 12

one sec

Answer 13

1 mississippi....

Answer 14

well, h(0)=1 ?

Answer 15

okay (:

Answer 16

and h(pi/4) is -2

Answer 17

keep going...
2 mississippi...

Answer 18

ok... good...

Answer 19

and since the signs are opposite then their is a 0

Answer 20

i see