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Mathematics 13 Online
OpenStudy (anonymous):

The figure below shows the top view of a circular room with a circular stage. The diameter of the stage is 24 feet. The shaded portion represents the seating for the audience around the stage. What is the area of the seating portion?

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Any ideas to get started?

OpenStudy (anonymous):

find the area of the cirlce in general?

jimthompson5910 (jim_thompson5910):

That's a good first step

jimthompson5910 (jim_thompson5910):

So what is the area of the larger circle?

OpenStudy (anonymous):

11304

jimthompson5910 (jim_thompson5910):

how did you get that? I'm assuming you did pi*r^2 right?

OpenStudy (anonymous):

yeah thats what i did!

jimthompson5910 (jim_thompson5910):

ok, It's probably better to leave it in terms of pi

jimthompson5910 (jim_thompson5910):

So A = pi*r^2 A = pi*60^2 A = 3600pi

OpenStudy (anonymous):

alright...now what do i do?

jimthompson5910 (jim_thompson5910):

now what is the area of the smaller circle?

OpenStudy (anonymous):

452.16 or it be 144pi

jimthompson5910 (jim_thompson5910):

144pi is what I'd go with

jimthompson5910 (jim_thompson5910):

So the area of the outer ring is (Area of larger circle) - (Area of smaller circle) = 3600pi - 144pi = 3456pi

jimthompson5910 (jim_thompson5910):

This is NOT the final answer as this includes that non-shaded bit in the outer ring.

OpenStudy (anonymous):

right. how do i find out how much of the circle is not shaded?

jimthompson5910 (jim_thompson5910):

Now we turn to the formula for the area of a sector Area = (angle/360)*pi*r^2 Does this formula look familiar?

OpenStudy (anonymous):

a little bit. ive seen way to many formulas haha

jimthompson5910 (jim_thompson5910):

Basically, if you have a pie shaded sector (or pizza slice shaped sector) and you know the angle from the center that it makes like in the drawing below, then you can find the area of this slice |dw:1341442006502:dw|

jimthompson5910 (jim_thompson5910):

The angle of that pizza slice is x, so the area of that slice is then A = (x/360)*pi*r^2

OpenStudy (anonymous):

which in this case would be (70/360)*pi*r^2...right?

jimthompson5910 (jim_thompson5910):

You got it

jimthompson5910 (jim_thompson5910):

You would just use different values of r

jimthompson5910 (jim_thompson5910):

r = 60 for the larger slice and r = 12 for the smaller slice

jimthompson5910 (jim_thompson5910):

the piece that is missing in the outer ring would then be equal to the difference in those areas

OpenStudy (anonymous):

alright!! i get it now!

jimthompson5910 (jim_thompson5910):

alright great

jimthompson5910 (jim_thompson5910):

tell me what you get for the final answer

OpenStudy (anonymous):

alright...i hope this is right. i got 1348

jimthompson5910 (jim_thompson5910):

No it should be larger

jimthompson5910 (jim_thompson5910):

What did you get for the areas of each pizza slice?

OpenStudy (anonymous):

i got 2196 and 87.92

jimthompson5910 (jim_thompson5910):

Again I'd leave everything in terms of pi

OpenStudy (anonymous):

so 700pi and 28pi?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

Their difference is then 700pi - 28pi = 672pi

jimthompson5910 (jim_thompson5910):

So the missing piece in the outer ring (the unshaded bit in the outer ring) is 672pi

jimthompson5910 (jim_thompson5910):

This means that the shaded area is then... (Area of entire outer ring) - (Area of unshaded bit in outer ring) (3456pi) - (672pi) 2784pi

OpenStudy (anonymous):

and thats with that piece missing?

jimthompson5910 (jim_thompson5910):

yes that is the area of the shaded region as shown in the pic above

jimthompson5910 (jim_thompson5910):

aka the original pic given to you

OpenStudy (anonymous):

right! i forgot to multiply it by pi...oops haha

jimthompson5910 (jim_thompson5910):

If you want the approximate area, use pi = 3.14 to get 2784pi = 2784*3.14 = 8741.76

jimthompson5910 (jim_thompson5910):

lol that explains a lot

OpenStudy (anonymous):

no kidding. well AWESOME! thanks again so much! this really helped!

jimthompson5910 (jim_thompson5910):

I'm glad that's all clicking for you

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