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Mathematics 21 Online
OpenStudy (konradzuse):

solve the differential eq

OpenStudy (konradzuse):

dr/d0 = (sin(pi0))^4

OpenStudy (konradzuse):

0 = theata

OpenStudy (lgbasallote):

lol integrals then suddenly diff eq lol =)) your curriculum makes me wonder

OpenStudy (konradzuse):

IT makes EVERYONE wonder.....

OpenStudy (konradzuse):

It's like they want to add them in to get us ready for diff eq later...

OpenStudy (lgbasallote):

\[\frac{dr}{d\theta} = \sin^4 (\pi \theta)?\]

OpenStudy (konradzuse):

yessir.

OpenStudy (konradzuse):

\[dr = (\sin(\pi \theta))^4 d \theta\]

OpenStudy (lgbasallote):

now take the integral of both sides

OpenStudy (konradzuse):

so it's time for half angle formula!

OpenStudy (lgbasallote):

half angle?

OpenStudy (lgbasallote):

i think this is just some trig sub thingy

OpenStudy (konradzuse):

Unless just do it normally...

OpenStudy (lgbasallote):

\[\int \sin^4 (\pi \theta) d\theta\] treat pii like a variable

OpenStudy (lgbasallote):

i mean treat pi like a cosntant

OpenStudy (konradzuse):

I could say u = pi theta du = pi dtheta

OpenStudy (konradzuse):

\[1/\pi \int\limits \sin^4(u) du\]

OpenStudy (konradzuse):

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (lgbasallote):

yup you're doing well

OpenStudy (konradzuse):

you cann integrate that though...

OpenStudy (lgbasallote):

the integration of that is pretty long haha

OpenStudy (konradzuse):

I could do a half angle formula now :P

OpenStudy (lgbasallote):

what half lol

OpenStudy (konradzuse):

\[1/2\pi \int\limits (1-\cos2u)^2 du\]

OpenStudy (konradzuse):

WE!

OpenStudy (konradzuse):

\[1/2\pi \int\limits (1-\cos2u) (1-\cos2u) du\]

OpenStudy (konradzuse):

\[1/2\pi \int\limits) (1-2\cos2u +( \cos2u)^2)du\]

OpenStudy (konradzuse):

:p

OpenStudy (konradzuse):

ok I give up hahha.

OpenStudy (lgbasallote):

lol =)) like i said this integration is long

OpenStudy (lgbasallote):

just look at this :( http://www.wolframalpha.com/input/?i=int+sin%5E4+%28x%29dx

OpenStudy (lgbasallote):

long isnt it

OpenStudy (anonymous):

Power reduction formula, maybe?

OpenStudy (konradzuse):

maybe :P

OpenStudy (anonymous):

\(\sin^4(x)=\frac{1}{8}\left(3-4\cos(2x)+\cos(4x)\right)\)

OpenStudy (konradzuse):

Wolfram is wrong! :P

OpenStudy (anonymous):

Did you misunderstand? I said your statement is false for all possibilities.

OpenStudy (konradzuse):

I'll try your answer, it said wolfram's was incorrect.

OpenStudy (konradzuse):

Cool I win.

OpenStudy (anonymous):

@KonradZuse, I apologize if I made a comment earlier that offended you. Many of my rather crazy-sounding or outlandish statements are completely jokes. I had actually meant that original comment in a positive light--I was glad to see that you have taken interest in mathematics and enjoy it more than most people. I had said this to other users on OS and complimented you during conversations with them. Nonetheless, I apologize if my message came off completely contrary to how it was intended. I hope you'll forgive me. P.S. My original comment was also a joke on Paul Erdos. Once again, nothing mean was meant. Thanks, Limitless

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