When a block is placed on top of a vertical spring, the spring compresses 4.40 cm. Find the mass of the block, given that the force constant of the spring is 1700 N/m.

Question

anonymous · Answer

In a position of equilibrium ,
The spring force is equal to the weight

So,
kx = mg
m=kx/g
    = (1700)(4.4 /100)/ 9.8

anonymous · Answer

This is a question on spring constant. So F = kx
                                                           mg=kx
                                                             m=kx/g
                                                                =(1700)(0.044)/(100)
                                                                 =

                                                   NB: Change 4.40cm to m so you'll  divide 4.40 over 100.

anonymous · Answer

1700*(0.044)=M*(9.8)
so M=7.63kg

anonymous · Answer

at equillibrium force applied by spring will be equal to weight of the block.
so,
kx=mg,
and given k=1700N/M,
x=.044M
1700*.044 = weight of the block,
9.8*m = 1700*.044
where m is the mass of the block.