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Mathematics 20 Online
OpenStudy (anonymous):

Factor equation. x²-y²+2x+2y

OpenStudy (anonymous):

group it this way first: \(\large (x^2-y^2)+(2x+2y) \) factor that difference of squares... factor the GCF from the second grouping.... then you can prolly factor once more...

OpenStudy (anonymous):

\(\large (x^2-y^2)+(2x+2y) \) \(\large (x-y)(x+y)+2(x+y) \) \(\large (x-y)\color{red}{(x+y)}+2\color{red}{(x+y)} \)

OpenStudy (anonymous):

Ok, when I got to your last step, should (x+y) be the answer sinced its factored?

OpenStudy (anonymous):

no... the terms both have the same factor of (x+y)... that can be factored out....

OpenStudy (anonymous):

|dw:1341452159134:dw|

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