Question

Multiplying Radicals:
sqrt12 * sqrt3xy^2

Answer 1

Is this your question?
\[\sqrt {12} \times \sqrt{3xy^2}\]

Answer 2

yeah I just don't know how to do the radical thing

Answer 3

You can use equation editor for this

Answer 4

Ok let's work on the problem!
if we have
\[\sqrt{A} \times \sqrt{B}\]
if A and B are positive then it's equivalent to
\[\sqrt{AB}\]
Could you tell what we'll get after multiplying the two radicals?

Answer 5

are we multiplying 12 and 3?

Answer 6

We are multiplying
\[12\times 3 xy^2\]

Answer 7

that leaves 36xy^2

Answer 8

good, so we have now
\[\sqrt{36xy^2}\]
Now can you simplify it further?

Answer 9

Not sure. I never learned this in school and my teacher for virtual school is off for the next few days.

Answer 10

Okay do you know the square root of 36 ?

Answer 11

6

Answer 12

It's because we
\[\sqrt{36}=\sqrt {6\times 6}=6\]
here we have
\[\sqrt{36xy^2}=\sqrt{6\times 6\times x\times y\times y}\]
Could you simplify it now?
only the terms appearing twice come out, as 1 term

Answer 13

it would be 6x?

Answer 14

only y and 6 appear twice, they will come out. x will remain inside
\[\sqrt{6\times 6 \times x\times y\times y}=6y\sqrt{x}\]
Do you get this?

Answer 15

Oh I didn't quite understand what you meant by "come out" but yes now I understand it.

Answer 16

Did you understand? What's the square root of 64x^2?
\[\sqrt{64x^2}\]

Answer 17

8x?

Answer 18

good work:D