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Mathematics 7 Online
OpenStudy (anonymous):

The position of a function is given by s(t)=4t²+2t+3, where s is measured in feet and t in seconds. Find the velocity of the object at time t=2 seconds.

OpenStudy (anonymous):

Let \(t=2\).

OpenStudy (anonymous):

or, "Plug in" \(2\).

OpenStudy (anonymous):

oh okay thanks!

OpenStudy (anonymous):

if u just plug in 2, u only get distance, which is measured in feet

OpenStudy (anonymous):

so the answer would be 23 ft/s²?

OpenStudy (anonymous):

the derivative of a distance function represents instantaneous velocity, so u need to get the derivative of that function 1st, then plug in t=2~

OpenStudy (anonymous):

Oh.. This is Physics, not math. @Iyy1992 is right; I did not read it entirely.

OpenStudy (anonymous):

v=s'(t)=8t+2+0, plug in t=2 >>> 18. hope helps

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