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The position of a function is given by s(t)=4t²+2t+3, where s is measured in feet and t in seconds. Find the velocity of the object at time t=2 seconds.
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Let \(t=2\).
or, "Plug in" \(2\).
oh okay thanks!
if u just plug in 2, u only get distance, which is measured in feet
so the answer would be 23 ft/s²?
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the derivative of a distance function represents instantaneous velocity, so u need to get the derivative of that function 1st, then plug in t=2~
Oh.. This is Physics, not math. @Iyy1992 is right; I did not read it entirely.
v=s'(t)=8t+2+0, plug in t=2 >>> 18. hope helps
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