Question

Simplify 2log(-2)

Answer 1

I got \[2*\log(-2) = \log(-2)^{2} = \log(4)\] but it's wrong...why?

Answer 2

that value (=-2), that can't be negative, it is always greater than 0.

Answer 3

\[2\log_{}{-2}\implies \log_{}{-2^2}\]
can u do it from here???

Answer 4

\[\log ((-2)^{2}) = \log4\]

Answer 5

Ya!!

Answer 6

My teacher says it's the wrong answer

Answer 7

\[\log_{}{-2\times -2} =\log_{4} \]How can it be wrong?

Answer 8

She says it's \[2\log(-2) = \log(-(2^{2})) = \log(-4)\]

Answer 9

Sorry, it's\[\log_{}{4} \]

Answer 10

Oops, I am wrong . she is right. I haven't see that thing.

Answer 11

How is she right?

Answer 12

perplexing,..

Answer 13

@failmathmajor what is in the base?

Answer 14

base of log??

Answer 15

@failmathmajor the answer does not exist because logarithms cannot be negative like what @shubham.bagrecha said even though it will become positive when squared