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how do you expand logs...
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\[ \log_{2} y^{5}/3\]
is it \[\log_{2}(y ^{5}/3) \]?
yes!
\[\huge \color{blue}{Log(\frac{a}{b}) = Log(a) - Log(b)}\] \[\huge \color{red}{Log(a)^b = b \times Log(a)}\]
\[\huge Log_2\frac{(y^5)}{3} = Log_2(y)^5 - Log_2(3)\]
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Now use the second formula to simplify \(Log_2(y)^5\)..
5Log(y)...?
Yes.. Don't forget to write the base(2)..
\[5\log_{2} y\]
Yes you are right dear..
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So, total answer becomes: \[\huge \color{pink}{= 5Log_2(y) - Log_2(3)}\]
thanksss
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