Given the following, x1=2 x2=-1 x3=-2 x4=5 x5=-4 x6=8 Find: 3 ∑ ( x subi - 1 ) 2 i=1
I think I can handle this ;)
\[\sum_{i=1}^{i=3} (x_i - 1) ^2 \]
the suspense is killing me :)
You given 6 x_i values. The equation only wants you to consider x_i for (i=1 until i=3), that would be x1, x2, x3. The sigma is the symbol for sum. So the problem is to find the sum for the following events: plugging in each x_i subtracting 1 then squaring that. Hence you'll have 3 values that you then add to together to get the final value. \[ i=1, x_1 = 2, (2-1)^2 = 1\] \[i=2, x_2 = -1, ((-1) -1)^2 = ... \] ... and so on
could we expand the binomial and pick it apart sum for sum?
OH! THANK YOU. DPFLAN, you are the best <3
@amistre64 for sure, that would create even more suspense!
the butler did it, im sure of it ....
with the candlestick?
@sleestak No problem, glad I could help!
yes, with the candlestick lol ... get a clue
@sleestak I imagine you may have some more problems that are similar to this that you need to work on, so good luck
thanks. I'll tell you what I come up with
9
oh no. sorry one sec
14. OK. I think I can do the other problem. THANKS :D
x1 -> 1 x2 -> 4 x3 -> 9 SUM = 14, yeah, you're now an expert it seems
you guys need to list finance as the next subject :D
It actually had/has a pretty strong following/support from a professor at NYU - http://pages.stern.nyu.edu/~adamodar/
Math is the most active subject
oh. excellent.
So if your questions are mathematical, you'd probably be best served to ask them here because there is a greater mass of users in this group, so you're more likely get an answer.
yeah totally. this is awesome! I am going to use this all the time in school
awesome, tell your friends too! Also, I've the final question you asked about solved
*got
oh okay. let me post
should I now 'close' this question?
Yep
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