Question

expand.. please tell me why there is 89 people online and not 1 has helped me on this problem... getting fiesty :/

Answer 1

\[\ln \sqrt[3]{x^2y}\]

Answer 2

@lgbasallote

Answer 3

could you enlarge the text?

Answer 4

how do i do that

Answer 5

\[\huge \ln \sqrt[3]{x^2y}?\]

Answer 6

\[\huge \ln \sqrt[3]{x^2y} \]

Answer 7

sorry i gotta go...lemme call on @ParthKohli for you

Answer 8

\(\color{Black}{\Rightarrow \ln \sqrt[3]{x^2y} = \ln (x^2y)\large ^{1 \over 3} }\) right?

Answer 9

okay thanks @igbasallote

Answer 10

\(\color{Black}{\Rightarrow \Large {1 \over 3}\ln x^2y }\)

\(\color{Black}{\Rightarrow \Large {1 \over3} \ln (xy^{1 \over 2})^2 }\)

\(\color{Black}{\Rightarrow {2 \over 3}\Large \ln x\sqrt y }\)

Answer 11

how did you get that?

Answer 12

Do you know the properties of logarithms?

Answer 13

everyone has asked that? i dont think i know them...

Answer 14

Okay, her'es a vital one:

\(\color{Black}{\Rightarrow \ln x^y = y \ln x}\)

Answer 15

Well you could just simplify it as:

\(\color{Black}{\Rightarrow \Large {1 \over 3} \ln x^2y }\)

Answer 16

ohhh okay!

Answer 17

thank youuuuuu

Answer 18

Even I had no idea what I was doing there lol but it's all good.

Answer 19

\[2lnx + 3lny\]