sec theta is negative, which quadrant does it belong?
if sec(theta) is negative, then as sec(theta) = 1/cos(theta), it must be that cos(theta) is also negative. Now can you answer the question?
None of this makes since to me, i have done got like 10 people on here trying to explain it to me, but i cant understand it for some reason.
Go back to the definition of cos(theta). Draw a unit circle centered at the origin, mark out an angle on that circle. What is the definition of cos(theta)? It is the x-ordinate of the ray corresponding to that angle: |dw:1341527786767:dw| apologies for the klug of a diagram
Remember that definition of cos(theta)?
i.e., cos(theta) = x. This is why cos(0) = 1, because when theta = 0, the ray corresponding to that value of theta lies along the positive x-axis and the point on the unit circle is (x,y) = (1,0). Similarly, cos(pi/2) = 0, because there the point on the unit circle is (x,y) = (0,1)
making sense so far?
No. :/
i dont understand what the whole theta, cos, tan, etc stuff means.
Have a look at the top part of this article: http://mathworld.wolfram.com/Cosine.html You will need to understand what sin and cos means in order to answer your question, obviously.
ok, so is the answer Q3?
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