Question

,

Answer 1

Well, what are the vertices of an ellipse in general centered around the origin:
\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]
?
Hint: clearly (a,0) is one of them as (x,y) = (a,0) satisfies the equation. What are the other three?

Once you can answer this question, your question and all others like it will be easy.

Answer 2

SO ITS BETWEEN B AND C

Answer 3

Instead of trying to use elimination, try and answer the general question and understand the concept over all.

One pair of vertices is (a,0) and (-a,0). What's the other pair of vertices?

Answer 4

IDK

Answer 5

(0,b) and (0,-b) is the other pair.

Now given that, what's the answer to your question? Look carefully at all of these vertices to this general equation.

Answer 6

i think its b

Answer 7

Given your vertices, (0, 2), (0, -2) and (3, 0), (-3, 0),
a = 3
b = 2

Now substitute these values into the general equation I gave above.

Answer 8

i dont know how to set it up.

Answer 9

is b correct?

Answer 10

No it's not.

The vertices of
x^2/a^2 + y^2/b^2 = 1

are
(a,0), (-a,0), (0,b), (0,-b)

Given your vertices we deduced that
a = 3 and b = 2.

Hence the equation of the ellipse MUST be

\[ \frac{x^2}{3^2} + \frac{y^2}{2^2} = 1 \]
Now you see the answer?

Answer 11

c!