Find the derivative of y with respect to x y= ln (1-x)/((x+2)^5)
anyone please!!
\[\left(\frac{a[x]}{b[x]}\right)'=\frac{a'[x]}{b[x]}-\frac{a[x] b'[x]}{b[x]^2} \]where a(x)=Log(1 - x) and b(x)=(x+2)^5
Is just the answer satisfactory?
hmm.
i dont get what the answer is.
\[-\frac{1}{(1-x) (x+2)^5}-\frac{5 \log (1-x)}{(x+2)^6} \]
i got ln (1-x)(5(x+2)^4 all over (x+2)^10
i dont have that as a choice.
try separating expanding the logarthm first: \[\large y=ln\frac{1-x}{(x+2)^5}=ln(1-x)-5ln(x+2) \]
what happened to the so we dont need to make it 5 ln (x+2)^4?
i think finding the derivative will be easier from here if you use y'/y
@MegMegs4 , no... it's the property of logs...\(\large log_bM^n=nlog_bM \)
oh ok i think thats where i was making my mistake.
so i got.... -1/(1-x) - 5/(x+2)
that looks good...:)
ok but it isnt one of my answer choices.
subtract them....
my choices are a. (x+2)^5 / (1-x) b. ln (6x-7)/(x+2)^6 c. 4x-7 / (x+2)(1-x) d. 4x-7 /(x+2)^6
im trying it now.
yea... it looks as though they did subtract them..
so the answer is c!! thank you . you are so smart!!
that's what i got..
thanks... yw..:)
@dpaInc Isn't the problem equation the following ?\[y=\frac{\log (1-x)}{(x+2)^5} \]
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